Solve .06x+.08y=1840

$$.06 x + .08 y = 1840$$

Solve for x

$$x=\frac{92000-4y}{3}$$

Steps for Solving Linear Equation

Subtract 0.08y from both sides.

$$0.06x=1840-0.08y$$

The equation is in standard form.

$$0.06x=-\frac{2y}{25}+1840$$

Divide both sides of the equation by 0.06, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{0.06x}{0.06}=\frac{-\frac{2y}{25}+1840}{0.06}$$

Dividing by 0.06 undoes the multiplication by 0.06.

$$x=\frac{-\frac{2y}{25}+1840}{0.06}$$

Divide 1840-\frac{2y}{25} by 0.06 by multiplying 1840-\frac{2y}{25} by the reciprocal of 0.06.

$$x=\frac{92000-4y}{3}$$

Solve for y

$$y=-\frac{3x}{4}+23000$$

Steps for Solving Linear Equation

Subtract 0.06x from both sides.

$$0.08y=1840-0.06x$$

The equation is in standard form.

$$0.08y=-\frac{3x}{50}+1840$$

Divide both sides of the equation by 0.08, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{0.08y}{0.08}=\frac{-\frac{3x}{50}+1840}{0.08}$$

Dividing by 0.08 undoes the multiplication by 0.08.

$$y=\frac{-\frac{3x}{50}+1840}{0.08}$$

Divide 1840-\frac{3x}{50} by 0.08 by multiplying 1840-\frac{3x}{50} by the reciprocal of 0.08.

$$y=-\frac{3x}{4}+23000$$