Solve for x
x=\frac{y+9}{3}
Solve for y
y=3\left(x-3\right)
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9-3x=-y
Swap sides so that all variable terms are on the left hand side.
-3x=-y-9
Subtract 9 from both sides.
\frac{-3x}{-3}=\frac{-y-9}{-3}
Divide both sides by -3.
x=\frac{-y-9}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{y}{3}+3
Divide -y-9 by -3.
-y=9-3x
The equation is in standard form.
\frac{-y}{-1}=\frac{9-3x}{-1}
Divide both sides by -1.
y=\frac{9-3x}{-1}
Dividing by -1 undoes the multiplication by -1.
y=3x-9
Divide 9-3x by -1.
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