Solve -f-6*06=1/2*06*10*03-1/2*06*16

$$-f-6 \cdot 06 = \frac{ 1 }{ 2 } \times 06 \cdot 10 \cdot 03- \frac{ 1 }{ 2 } \times 06 \cdot 16$$

Solve for f

$$f=0$$

Steps for Solving Linear Equation

Multiply 6 and 0 to get 0.

$$-f-0\times 6=\frac{1}{2}\times 0\times 6\times 10\times 0\times 3-\frac{1}{2}\times 0\times 6\times 16$$

Multiply 0 and 6 to get 0.

$$-f-0=\frac{1}{2}\times 0\times 6\times 10\times 0\times 3-\frac{1}{2}\times 0\times 6\times 16$$

Multiply \frac{1}{2} and 0 to get 0.

$$-f-0=0\times 6\times 10\times 0\times 3-\frac{1}{2}\times 0\times 6\times 16$$

Multiply 0 and 6 to get 0.

$$-f-0=0\times 10\times 0\times 3-\frac{1}{2}\times 0\times 6\times 16$$

Multiply 0 and 10 to get 0.

$$-f-0=0\times 0\times 3-\frac{1}{2}\times 0\times 6\times 16$$

Multiply 0 and 0 to get 0.

$$-f-0=0\times 3-\frac{1}{2}\times 0\times 6\times 16$$

Multiply 0 and 3 to get 0.

$$-f-0=0-\frac{1}{2}\times 0\times 6\times 16$$

Multiply \frac{1}{2} and 0 to get 0.

$$-f-0=0-0\times 6\times 16$$

Multiply 0 and 6 to get 0.

$$-f-0=0-0\times 16$$

Multiply 0 and 16 to get 0.

$$-f-0=0-0$$

Subtracting 0 from itself leaves 0.

$$-f-0=0$$

Add 0 to both sides.

$$-f=0+0$$

Add 0 and 0 to get 0.

$$-f=0$$

Product of two numbers is equal to 0 if at least one of them is 0. Since -1 is not equal to 0, f must be equal to 0.

$$f=0$$