Solve for x
x=-\frac{5y}{9}-\frac{4}{3}
Solve for y
y=\frac{-9x-12}{5}
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-9x=12+5y
Add 5y to both sides.
-9x=5y+12
The equation is in standard form.
\frac{-9x}{-9}=\frac{5y+12}{-9}
Divide both sides by -9.
x=\frac{5y+12}{-9}
Dividing by -9 undoes the multiplication by -9.
x=-\frac{5y}{9}-\frac{4}{3}
Divide 12+5y by -9.
-5y=12+9x
Add 9x to both sides.
-5y=9x+12
The equation is in standard form.
\frac{-5y}{-5}=\frac{9x+12}{-5}
Divide both sides by -5.
y=\frac{9x+12}{-5}
Dividing by -5 undoes the multiplication by -5.
y=\frac{-9x-12}{5}
Divide 12+9x by -5.
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