Solve -9sqrt{3x+39}=-27

$$-9 \sqrt{ 3x+39 } =-27$$

Solve for x

$$x=-10$$

Steps for Solving Radical Equations

Divide both sides by -9.

$$\frac{-9\sqrt{3x+39}}{-9}=-\frac{27}{-9}$$

Dividing by -9 undoes the multiplication by -9.

$$\sqrt{3x+39}=-\frac{27}{-9}$$

Divide -27 by -9.

$$\sqrt{3x+39}=3$$

Square both sides of the equation.

$$3x+39=9$$

Subtract 39 from both sides of the equation.

$$3x+39-39=9-39$$

Subtracting 39 from itself leaves 0.

$$3x=9-39$$

Subtract 39 from 9.

$$3x=-30$$

Divide both sides by 3.

$$\frac{3x}{3}=-\frac{30}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$x=-\frac{30}{3}$$

Divide -30 by 3.

$$x=-10$$