Solve -8x-8+(-2x)-1

$$-8x-8+(-2x)-1$$

Evaluate

$$-10x-9$$

Solution Steps

Combine -8x and -2x to get -10x.

$$-10x-8-1$$

Subtract 1 from -8 to get -9.

$$-10x-9$$

Differentiate w.r.t. x

$$-10$$

Steps Using Derivative Rule for Sum

Combine -8x and -2x to get -10x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-10x-8-1)$$

Subtract 1 from -8 to get -9.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-10x-9)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-10x^{1-1}$$

Subtract 1 from 1.

$$-10x^{0}$$

For any term t except 0, t^{0}=1.

$$-10$$