Solve -8(3+x)+3(3-x)-5=-6x-10(x+2)

$$-8(3+x)+3(3-x)-5=-6x-10(x+2)$$

Solve for x

$$x=0$$

Steps for Solving Linear Equation

Use the distributive property to multiply -8 by 3+x.

$$-24-8x+3\left(3-x\right)-5=-6x-10\left(x+2\right)$$

Use the distributive property to multiply 3 by 3-x.

$$-24-8x+9-3x-5=-6x-10\left(x+2\right)$$

Add -24 and 9 to get -15.

$$-15-8x-3x-5=-6x-10\left(x+2\right)$$

Combine -8x and -3x to get -11x.

$$-15-11x-5=-6x-10\left(x+2\right)$$

Subtract 5 from -15 to get -20.

$$-20-11x=-6x-10\left(x+2\right)$$

Use the distributive property to multiply -10 by x+2.

$$-20-11x=-6x-10x-20$$

Combine -6x and -10x to get -16x.

$$-20-11x=-16x-20$$

Add 16x to both sides.

$$-20-11x+16x=-20$$

Combine -11x and 16x to get 5x.

$$-20+5x=-20$$

Add 20 to both sides.

$$5x=-20+20$$

Add -20 and 20 to get 0.

$$5x=0$$

Product of two numbers is equal to 0 if at least one of them is 0. Since 5 is not equal to 0, x must be equal to 0.

$$x=0$$