Solve -87/16+1019/24-33/8

$$-8 \frac{ 7 }{ 16 } +10 \frac{ 19 }{ 24 } -3 \frac{ 3 }{ 8 }$$

Evaluate

$$-\frac{49}{48}\approx -1.020833333$$

Solution Steps

Multiply 8 and 16 to get 128.

$$-\frac{128+7}{16}+\frac{10\times 24+19}{24}-\frac{3\times 8+3}{8}$$

Add 128 and 7 to get 135.

$$-\frac{135}{16}+\frac{10\times 24+19}{24}-\frac{3\times 8+3}{8}$$

Multiply 10 and 24 to get 240.

$$-\frac{135}{16}+\frac{240+19}{24}-\frac{3\times 8+3}{8}$$

Add 240 and 19 to get 259.

$$-\frac{135}{16}+\frac{259}{24}-\frac{3\times 8+3}{8}$$

Least common multiple of 16 and 24 is 48. Convert -\frac{135}{16} and \frac{259}{24} to fractions with denominator 48.

$$-\frac{405}{48}+\frac{518}{48}-\frac{3\times 8+3}{8}$$

Since -\frac{405}{48} and \frac{518}{48} have the same denominator, add them by adding their numerators.

$$\frac{-405+518}{48}-\frac{3\times 8+3}{8}$$

Add -405 and 518 to get 113.

$$\frac{113}{48}-\frac{3\times 8+3}{8}$$

Multiply 3 and 8 to get 24.

$$\frac{113}{48}-\frac{24+3}{8}$$

Add 24 and 3 to get 27.

$$\frac{113}{48}-\frac{27}{8}$$

Least common multiple of 48 and 8 is 48. Convert \frac{113}{48} and \frac{27}{8} to fractions with denominator 48.

$$\frac{113}{48}-\frac{162}{48}$$

Since \frac{113}{48} and \frac{162}{48} have the same denominator, subtract them by subtracting their numerators.

$$\frac{113-162}{48}$$

Subtract 162 from 113 to get -49.

$$-\frac{49}{48}$$

Factor

$$-\frac{49}{48} = -1\frac{1}{48} = -1.0208333333333333$$