Solve -7geq3-5x/5

$$-7 \geq \frac{ 3-5x }{ 5 }$$

Solve for x

$$x\geq \frac{38}{5}$$

Solution Steps

Multiply both sides by 5. Since 5 is positive, the inequality direction remains the same.

$$-7\times 5\geq 3-5x$$

Multiply -7 and 5 to get -35.

$$-35\geq 3-5x$$

Swap sides so that all variable terms are on the left hand side. This changes the sign direction.

$$3-5x\leq -35$$

Subtract 3 from both sides.

$$-5x\leq -35-3$$

Subtract 3 from -35 to get -38.

$$-5x\leq -38$$

Divide both sides by -5. Since -5 is negative, the inequality direction is changed.

$$x\geq \frac{-38}{-5}$$

Fraction \frac{-38}{-5} can be simplified to \frac{38}{5} by removing the negative sign from both the numerator and the denominator.

$$x\geq \frac{38}{5}$$