Solve for x
x=\frac{y-3}{3}
Solve for y
y=3\left(x+1\right)
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-6x=6-2y
The equation is in standard form.
\frac{-6x}{-6}=\frac{6-2y}{-6}
Divide both sides by -6.
x=\frac{6-2y}{-6}
Dividing by -6 undoes the multiplication by -6.
x=\frac{y}{3}-1
Divide -2y+6 by -6.
-2y+6=-6x
Swap sides so that all variable terms are on the left hand side.
-2y=-6x-6
Subtract 6 from both sides.
\frac{-2y}{-2}=\frac{-6x-6}{-2}
Divide both sides by -2.
y=\frac{-6x-6}{-2}
Dividing by -2 undoes the multiplication by -2.
y=3x+3
Divide -6x-6 by -2.
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