Solve -6u^2+8u-2+5u^2+5u-3-5u^2-3u-1

$$-6 { u }^{ 2 } +8u-2+5 { u }^{ 2 } +5u-3-5 { u }^{ 2 } -3u-1$$

Evaluate

$$-6u^{2}+10u-6$$

Solution Steps

Combine -6u^{2} and 5u^{2} to get -u^{2}.

$$-u^{2}+8u-2+5u-3-5u^{2}-3u-1$$

Combine 8u and 5u to get 13u.

$$-u^{2}+13u-2-3-5u^{2}-3u-1$$

Subtract 3 from -2 to get -5.

$$-u^{2}+13u-5-5u^{2}-3u-1$$

Combine -u^{2} and -5u^{2} to get -6u^{2}.

$$-6u^{2}+13u-5-3u-1$$

Combine 13u and -3u to get 10u.

$$-6u^{2}+10u-5-1$$

Subtract 1 from -5 to get -6.

$$-6u^{2}+10u-6$$

Factor

$$2\left(-3u^{2}+5u-3\right)$$

Solution Steps

Multiply and combine like terms.

$$-6u^{2}+10u-6$$

Factor out 2. Polynomial -3u^{2}+5u-3 is not factored since it does not have any rational roots.

$$2\left(-3u^{2}+5u-3\right)$$