Solve for x
x=\frac{5y}{8}-\frac{9}{4}
Solve for y
y=\frac{8x+18}{5}
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8x=-18+5y
Add 5y to both sides.
8x=5y-18
The equation is in standard form.
\frac{8x}{8}=\frac{5y-18}{8}
Divide both sides by 8.
x=\frac{5y-18}{8}
Dividing by 8 undoes the multiplication by 8.
x=\frac{5y}{8}-\frac{9}{4}
Divide -18+5y by 8.
-5y=-18-8x
Subtract 8x from both sides.
-5y=-8x-18
The equation is in standard form.
\frac{-5y}{-5}=\frac{-8x-18}{-5}
Divide both sides by -5.
y=\frac{-8x-18}{-5}
Dividing by -5 undoes the multiplication by -5.
y=\frac{8x+18}{5}
Divide -18-8x by -5.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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