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-5x^{2}+10x+7-x^{2}
Combine 6x and 4x to get 10x.
-6x^{2}+10x+7
Combine -5x^{2} and -x^{2} to get -6x^{2}.
factor(-5x^{2}+10x+7-x^{2})
Combine 6x and 4x to get 10x.
factor(-6x^{2}+10x+7)
Combine -5x^{2} and -x^{2} to get -6x^{2}.
-6x^{2}+10x+7=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-10±\sqrt{10^{2}-4\left(-6\right)\times 7}}{2\left(-6\right)}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-10±\sqrt{100-4\left(-6\right)\times 7}}{2\left(-6\right)}
Square 10.
x=\frac{-10±\sqrt{100+24\times 7}}{2\left(-6\right)}
Multiply -4 times -6.
x=\frac{-10±\sqrt{100+168}}{2\left(-6\right)}
Multiply 24 times 7.
x=\frac{-10±\sqrt{268}}{2\left(-6\right)}
Add 100 to 168.
x=\frac{-10±2\sqrt{67}}{2\left(-6\right)}
Take the square root of 268.
x=\frac{-10±2\sqrt{67}}{-12}
Multiply 2 times -6.
x=\frac{2\sqrt{67}-10}{-12}
Now solve the equation x=\frac{-10±2\sqrt{67}}{-12} when ± is plus. Add -10 to 2\sqrt{67}.
x=\frac{5-\sqrt{67}}{6}
Divide -10+2\sqrt{67} by -12.
x=\frac{-2\sqrt{67}-10}{-12}
Now solve the equation x=\frac{-10±2\sqrt{67}}{-12} when ± is minus. Subtract 2\sqrt{67} from -10.
x=\frac{\sqrt{67}+5}{6}
Divide -10-2\sqrt{67} by -12.
-6x^{2}+10x+7=-6\left(x-\frac{5-\sqrt{67}}{6}\right)\left(x-\frac{\sqrt{67}+5}{6}\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute \frac{5-\sqrt{67}}{6} for x_{1} and \frac{5+\sqrt{67}}{6} for x_{2}.