Solve for x
x=\frac{3-y}{2}
Solve for y
y=3-2x
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-4x+6=2y
Add 2y to both sides. Anything plus zero gives itself.
-4x=2y-6
Subtract 6 from both sides.
\frac{-4x}{-4}=\frac{2y-6}{-4}
Divide both sides by -4.
x=\frac{2y-6}{-4}
Dividing by -4 undoes the multiplication by -4.
x=\frac{3-y}{2}
Divide -6+2y by -4.
-2y+6=4x
Add 4x to both sides. Anything plus zero gives itself.
-2y=4x-6
Subtract 6 from both sides.
\frac{-2y}{-2}=\frac{4x-6}{-2}
Divide both sides by -2.
y=\frac{4x-6}{-2}
Dividing by -2 undoes the multiplication by -2.
y=3-2x
Divide 4x-6 by -2.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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