Solve -4.9x^2+100x-300=0

$$-4.9 { x }^{ 2 } +100x-300 = 0$$

Solve for x

$$x = \frac{10 \sqrt{1030} + 500}{49} \approx 16.753798586$$

$$x = \frac{500 - 10 \sqrt{1030}}{49} \approx 3.654364679$$

Steps Using the Quadratic Formula

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$-4.9x^{2}+100x-300=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute -4.9 for a, 100 for b, and -300 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-100±\sqrt{100^{2}-4\left(-4.9\right)\left(-300\right)}}{2\left(-4.9\right)}$$

Square 100.

$$x=\frac{-100±\sqrt{10000-4\left(-4.9\right)\left(-300\right)}}{2\left(-4.9\right)}$$

Multiply -4 times -4.9.

$$x=\frac{-100±\sqrt{10000+19.6\left(-300\right)}}{2\left(-4.9\right)}$$

Multiply 19.6 times -300.

$$x=\frac{-100±\sqrt{10000-5880}}{2\left(-4.9\right)}$$

Add 10000 to -5880.

$$x=\frac{-100±\sqrt{4120}}{2\left(-4.9\right)}$$

Take the square root of 4120.

$$x=\frac{-100±2\sqrt{1030}}{2\left(-4.9\right)}$$

Multiply 2 times -4.9.

$$x=\frac{-100±2\sqrt{1030}}{-9.8}$$

Now solve the equation x=\frac{-100±2\sqrt{1030}}{-9.8} when ± is plus. Add -100 to 2\sqrt{1030}.

$$x=\frac{2\sqrt{1030}-100}{-9.8}$$

Divide -100+2\sqrt{1030} by -9.8 by multiplying -100+2\sqrt{1030} by the reciprocal of -9.8.

$$x=\frac{500-10\sqrt{1030}}{49}$$

Now solve the equation x=\frac{-100±2\sqrt{1030}}{-9.8} when ± is minus. Subtract 2\sqrt{1030} from -100.

$$x=\frac{-2\sqrt{1030}-100}{-9.8}$$

Divide -100-2\sqrt{1030} by -9.8 by multiplying -100-2\sqrt{1030} by the reciprocal of -9.8.

$$x=\frac{10\sqrt{1030}+500}{49}$$

The equation is now solved.

$$x=\frac{500-10\sqrt{1030}}{49} x=\frac{10\sqrt{1030}+500}{49}$$

Steps for Completing the Square

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

$$-4.9x^{2}+100x-300=0$$

Add 300 to both sides of the equation.

$$-4.9x^{2}+100x-300-\left(-300\right)=-\left(-300\right)$$

Subtracting -300 from itself leaves 0.

$$-4.9x^{2}+100x=-\left(-300\right)$$

Subtract -300 from 0.

$$-4.9x^{2}+100x=300$$

Divide both sides of the equation by -4.9, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-4.9x^{2}+100x}{-4.9}=\frac{300}{-4.9}$$

Dividing by -4.9 undoes the multiplication by -4.9.

$$x^{2}+\frac{100}{-4.9}x=\frac{300}{-4.9}$$

Divide 100 by -4.9 by multiplying 100 by the reciprocal of -4.9.

$$x^{2}-\frac{1000}{49}x=\frac{300}{-4.9}$$

Divide 300 by -4.9 by multiplying 300 by the reciprocal of -4.9.

$$x^{2}-\frac{1000}{49}x=-\frac{3000}{49}$$

Divide -\frac{1000}{49}, the coefficient of the x term, by 2 to get -\frac{500}{49}. Then add the square of -\frac{500}{49} to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}-\frac{1000}{49}x+\left(-\frac{500}{49}\right)^{2}=-\frac{3000}{49}+\left(-\frac{500}{49}\right)^{2}$$

Square -\frac{500}{49} by squaring both the numerator and the denominator of the fraction.

$$x^{2}-\frac{1000}{49}x+\frac{250000}{2401}=-\frac{3000}{49}+\frac{250000}{2401}$$

Add -\frac{3000}{49} to \frac{250000}{2401} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.

$$x^{2}-\frac{1000}{49}x+\frac{250000}{2401}=\frac{103000}{2401}$$

Factor x^{2}-\frac{1000}{49}x+\frac{250000}{2401}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-\frac{500}{49}\right)^{2}=\frac{103000}{2401}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x-\frac{500}{49}\right)^{2}}=\sqrt{\frac{103000}{2401}}$$

Simplify.

$$x-\frac{500}{49}=\frac{10\sqrt{1030}}{49} x-\frac{500}{49}=-\frac{10\sqrt{1030}}{49}$$

Add \frac{500}{49} to both sides of the equation.

$$x=\frac{10\sqrt{1030}+500}{49} x=\frac{500-10\sqrt{1030}}{49}$$