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-4.9x^{2}+1.2x=1.5
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
-4.9x^{2}+1.2x-1.5=1.5-1.5
Subtract 1.5 from both sides of the equation.
-4.9x^{2}+1.2x-1.5=0
Subtracting 1.5 from itself leaves 0.
x=\frac{-1.2±\sqrt{1.2^{2}-4\left(-4.9\right)\left(-1.5\right)}}{2\left(-4.9\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -4.9 for a, 1.2 for b, and -1.5 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-1.2±\sqrt{1.44-4\left(-4.9\right)\left(-1.5\right)}}{2\left(-4.9\right)}
Square 1.2 by squaring both the numerator and the denominator of the fraction.
x=\frac{-1.2±\sqrt{1.44+19.6\left(-1.5\right)}}{2\left(-4.9\right)}
Multiply -4 times -4.9.
x=\frac{-1.2±\sqrt{1.44-29.4}}{2\left(-4.9\right)}
Multiply 19.6 times -1.5 by multiplying numerator times numerator and denominator times denominator. Then reduce the fraction to lowest terms if possible.
x=\frac{-1.2±\sqrt{-27.96}}{2\left(-4.9\right)}
Add 1.44 to -29.4 by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
x=\frac{-1.2±\frac{\sqrt{699}i}{5}}{2\left(-4.9\right)}
Take the square root of -27.96.
x=\frac{-1.2±\frac{\sqrt{699}i}{5}}{-9.8}
Multiply 2 times -4.9.
x=\frac{-6+\sqrt{699}i}{-9.8\times 5}
Now solve the equation x=\frac{-1.2±\frac{\sqrt{699}i}{5}}{-9.8} when ± is plus. Add -1.2 to \frac{i\sqrt{699}}{5}.
x=\frac{-\sqrt{699}i+6}{49}
Divide \frac{-6+i\sqrt{699}}{5} by -9.8 by multiplying \frac{-6+i\sqrt{699}}{5} by the reciprocal of -9.8.
x=\frac{-\sqrt{699}i-6}{-9.8\times 5}
Now solve the equation x=\frac{-1.2±\frac{\sqrt{699}i}{5}}{-9.8} when ± is minus. Subtract \frac{i\sqrt{699}}{5} from -1.2.
x=\frac{6+\sqrt{699}i}{49}
Divide \frac{-6-i\sqrt{699}}{5} by -9.8 by multiplying \frac{-6-i\sqrt{699}}{5} by the reciprocal of -9.8.
x=\frac{-\sqrt{699}i+6}{49} x=\frac{6+\sqrt{699}i}{49}
The equation is now solved.
-4.9x^{2}+1.2x=1.5
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
\frac{-4.9x^{2}+1.2x}{-4.9}=\frac{1.5}{-4.9}
Divide both sides of the equation by -4.9, which is the same as multiplying both sides by the reciprocal of the fraction.
x^{2}+\frac{1.2}{-4.9}x=\frac{1.5}{-4.9}
Dividing by -4.9 undoes the multiplication by -4.9.
x^{2}-\frac{12}{49}x=\frac{1.5}{-4.9}
Divide 1.2 by -4.9 by multiplying 1.2 by the reciprocal of -4.9.
x^{2}-\frac{12}{49}x=-\frac{15}{49}
Divide 1.5 by -4.9 by multiplying 1.5 by the reciprocal of -4.9.
x^{2}-\frac{12}{49}x+\left(-\frac{6}{49}\right)^{2}=-\frac{15}{49}+\left(-\frac{6}{49}\right)^{2}
Divide -\frac{12}{49}, the coefficient of the x term, by 2 to get -\frac{6}{49}. Then add the square of -\frac{6}{49} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-\frac{12}{49}x+\frac{36}{2401}=-\frac{15}{49}+\frac{36}{2401}
Square -\frac{6}{49} by squaring both the numerator and the denominator of the fraction.
x^{2}-\frac{12}{49}x+\frac{36}{2401}=-\frac{699}{2401}
Add -\frac{15}{49} to \frac{36}{2401} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(x-\frac{6}{49}\right)^{2}=-\frac{699}{2401}
Factor x^{2}-\frac{12}{49}x+\frac{36}{2401}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-\frac{6}{49}\right)^{2}}=\sqrt{-\frac{699}{2401}}
Take the square root of both sides of the equation.
x-\frac{6}{49}=\frac{\sqrt{699}i}{49} x-\frac{6}{49}=-\frac{\sqrt{699}i}{49}
Simplify.
x=\frac{6+\sqrt{699}i}{49} x=\frac{-\sqrt{699}i+6}{49}
Add \frac{6}{49} to both sides of the equation.