Solve for a
a=\frac{b}{3}-\frac{c}{9}-\frac{4}{9}
Solve for b
b=\frac{9a+c+4}{3}
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9a-3b+c=-4
Swap sides so that all variable terms are on the left hand side.
9a+c=-4+3b
Add 3b to both sides.
9a=-4+3b-c
Subtract c from both sides.
9a=3b-c-4
The equation is in standard form.
\frac{9a}{9}=\frac{3b-c-4}{9}
Divide both sides by 9.
a=\frac{3b-c-4}{9}
Dividing by 9 undoes the multiplication by 9.
a=\frac{b}{3}-\frac{c}{9}-\frac{4}{9}
Divide -4+3b-c by 9.
9a-3b+c=-4
Swap sides so that all variable terms are on the left hand side.
-3b+c=-4-9a
Subtract 9a from both sides.
-3b=-4-9a-c
Subtract c from both sides.
-3b=-9a-c-4
The equation is in standard form.
\frac{-3b}{-3}=\frac{-9a-c-4}{-3}
Divide both sides by -3.
b=\frac{-9a-c-4}{-3}
Dividing by -3 undoes the multiplication by -3.
b=\frac{c}{3}+3a+\frac{4}{3}
Divide -4-9a-c by -3.
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