Solve -4+(6-3/7)=(4+6)-3/7

$$-4+(6- \frac{ 3 }{ 7 } )=(4+6)- \frac{ 3 }{ 7 }$$

Verify

Solution Steps

Add -4 and 6 to get 2.

$$2-\frac{3}{7}=4+6-\frac{3}{7}$$

Convert 2 to fraction \frac{14}{7}.

$$\frac{14}{7}-\frac{3}{7}=4+6-\frac{3}{7}$$

Since \frac{14}{7} and \frac{3}{7} have the same denominator, subtract them by subtracting their numerators.

$$\frac{14-3}{7}=4+6-\frac{3}{7}$$

Subtract 3 from 14 to get 11.

$$\frac{11}{7}=4+6-\frac{3}{7}$$

Add 4 and 6 to get 10.

$$\frac{11}{7}=10-\frac{3}{7}$$

Convert 10 to fraction \frac{70}{7}.

$$\frac{11}{7}=\frac{70}{7}-\frac{3}{7}$$

Since \frac{70}{7} and \frac{3}{7} have the same denominator, subtract them by subtracting their numerators.

$$\frac{11}{7}=\frac{70-3}{7}$$

Subtract 3 from 70 to get 67.

$$\frac{11}{7}=\frac{67}{7}$$

Compare \frac{11}{7} and \frac{67}{7}.

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