Solve -4+(-3-(-7-(-2-10)+(-8+5))+3)-2

$$-4+(-3-(-7-(-2-10)+(-8+5))+3)-2$$

Evaluate

$$-8$$

Solution Steps

Subtract 10 from -2 to get -12.

$$-4+-3-\left(-7-\left(-12\right)-8+5\right)+3-2$$

The opposite of -12 is 12.

$$-4+-3-\left(-7+12-8+5\right)+3-2$$

Add -7 and 12 to get 5.

$$-4+-3-\left(5-8+5\right)+3-2$$

Subtract 8 from 5 to get -3.

$$-4+-3-\left(-3+5\right)+3-2$$

Add -3 and 5 to get 2.

$$-4-3-2+3-2$$

Subtract 2 from -3 to get -5.

$$-4-5+3-2$$

Subtract 5 from -4 to get -9.

$$-9+3-2$$

Add -9 and 3 to get -6.

$$-6-2$$

Subtract 2 from -6 to get -8.

$$-8$$

Factor

$$-8$$