Solve -4+(-2+1)+5-(3-(1-2)+4)+1-2=

$$-4+(-2+1)+5-(3-(1-2)+4)+1-2=$$

Evaluate

$$-9$$

Solution Steps

Subtract 2 from -4 to get -6.

$$-6+1+5-\left(3-\left(1-2\right)+4\right)+1-2$$

Add -6 and 1 to get -5.

$$-5+5-\left(3-\left(1-2\right)+4\right)+1-2$$

Add -5 and 5 to get 0.

$$0-\left(3-\left(1-2\right)+4\right)+1-2$$

Subtract 2 from 1 to get -1.

$$0-\left(3-\left(-1\right)+4\right)+1-2$$

The opposite of -1 is 1.

$$0-\left(3+1+4\right)+1-2$$

Add 3 and 1 to get 4.

$$0-\left(4+4\right)+1-2$$

Add 4 and 4 to get 8.

$$0-8+1-2$$

Subtract 8 from 0 to get -8.

$$-8+1-2$$

Add -8 and 1 to get -7.

$$-7-2$$

Subtract 2 from -7 to get -9.

$$-9$$

Factor

$$-9$$