Solve -4{left(-1/4right)}^2-2(1/4)+6

$$-4 { \left(- \frac{ 1 }{ 4 } \right) }^{ 2 } -2( \frac{ 1 }{ 4 } )+6$$

Evaluate

$$\frac{21}{4}=5.25$$

Solution Steps

Calculate -\frac{1}{4} to the power of 2 and get \frac{1}{16}.

$$-4\times \frac{1}{16}-2\times \frac{1}{4}+6$$

Multiply -4 and \frac{1}{16} to get \frac{-4}{16}.

$$\frac{-4}{16}-2\times \frac{1}{4}+6$$

Reduce the fraction \frac{-4}{16} to lowest terms by extracting and canceling out 4.

$$-\frac{1}{4}-2\times \frac{1}{4}+6$$

Multiply 2 and \frac{1}{4} to get \frac{2}{4}.

$$-\frac{1}{4}-\frac{2}{4}+6$$

Since -\frac{1}{4} and \frac{2}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-1-2}{4}+6$$

Subtract 2 from -1 to get -3.

$$-\frac{3}{4}+6$$

Convert 6 to fraction \frac{24}{4}.

$$-\frac{3}{4}+\frac{24}{4}$$

Since -\frac{3}{4} and \frac{24}{4} have the same denominator, add them by adding their numerators.

$$\frac{-3+24}{4}$$

Add -3 and 24 to get 21.

$$\frac{21}{4}$$

Factor

$$\frac{3 \cdot 7}{2 ^ {2}} = 5\frac{1}{4} = 5.25$$