Solve -4div(-2/3)-5*left|-3right|

$$-4 \div (- \frac{ 2 }{ 3 } )-5 \times \left| -3 \right|$$

Evaluate

$$-9$$

Solution Steps

Divide -4 by -\frac{2}{3} by multiplying -4 by the reciprocal of -\frac{2}{3}.

$$-4\left(-\frac{3}{2}\right)-5|-3|$$

Express -4\left(-\frac{3}{2}\right) as a single fraction.

$$\frac{-4\left(-3\right)}{2}-5|-3|$$

Multiply -4 and -3 to get 12.

$$\frac{12}{2}-5|-3|$$

Divide 12 by 2 to get 6.

$$6-5|-3|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -3 is 3.

$$6-5\times 3$$

Multiply 5 and 3 to get 15.

$$6-15$$

Subtract 15 from 6 to get -9.

$$-9$$

Factor

$$-9$$