Solve for x
x=\frac{4\left(y-1\right)}{3}
Solve for y
y=\frac{3x}{4}+1
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-3x-4=-4y
Subtract 4y from both sides. Anything subtracted from zero gives its negation.
-3x=-4y+4
Add 4 to both sides.
-3x=4-4y
The equation is in standard form.
\frac{-3x}{-3}=\frac{4-4y}{-3}
Divide both sides by -3.
x=\frac{4-4y}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{4y-4}{3}
Divide -4y+4 by -3.
4y-4=3x
Add 3x to both sides. Anything plus zero gives itself.
4y=3x+4
Add 4 to both sides.
\frac{4y}{4}=\frac{3x+4}{4}
Divide both sides by 4.
y=\frac{3x+4}{4}
Dividing by 4 undoes the multiplication by 4.
y=\frac{3x}{4}+1
Divide 3x+4 by 4.
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