Solve -3(x-2)+15leq5

$$-3(x-2)+15 \leq 5$$

Solve for x

$$x\geq \frac{16}{3}$$

Solution Steps

Use the distributive property to multiply -3 by x-2.

$$-3x+6+15\leq 5$$

Add 6 and 15 to get 21.

$$-3x+21\leq 5$$

Subtract 21 from both sides.

$$-3x\leq 5-21$$

Subtract 21 from 5 to get -16.

$$-3x\leq -16$$

Divide both sides by -3. Since -3 is negative, the inequality direction is changed.

$$x\geq \frac{-16}{-3}$$

Fraction \frac{-16}{-3} can be simplified to \frac{16}{3} by removing the negative sign from both the numerator and the denominator.

$$x\geq \frac{16}{3}$$