Solve -3(x-2)geq2

$$-3(x-2) \geq 2$$

Solve for x

$$x\leq \frac{4}{3}$$

Solution Steps

Divide both sides by -3. Since -3 is negative, the inequality direction is changed.

$$x-2\leq -\frac{2}{3}$$

Add 2 to both sides.

$$x\leq -\frac{2}{3}+2$$

Convert 2 to fraction \frac{6}{3}.

$$x\leq -\frac{2}{3}+\frac{6}{3}$$

Since -\frac{2}{3} and \frac{6}{3} have the same denominator, add them by adding their numerators.

$$x\leq \frac{-2+6}{3}$$

Add -2 and 6 to get 4.

$$x\leq \frac{4}{3}$$