Solve -3x^2+3=0

$$-3 { x }^{ 2 } +3=0$$

Solve for x

$$x=1$$

$$x=-1$$

Steps by Finding Square Root

Subtract 3 from both sides. Anything subtracted from zero gives its negation.

$$-3x^{2}=-3$$

Divide both sides by -3.

$$x^{2}=\frac{-3}{-3}$$

Divide -3 by -3 to get 1.

$$x^{2}=1$$

Take the square root of both sides of the equation.

$$x=1 x=-1$$

Steps Using the Quadratic Formula

Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.

$$-3x^{2}+3=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute -3 for a, 0 for b, and 3 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-3\right)\times 3}}{2\left(-3\right)}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-3\right)\times 3}}{2\left(-3\right)}$$

Multiply -4 times -3.

$$x=\frac{0±\sqrt{12\times 3}}{2\left(-3\right)}$$

Multiply 12 times 3.

$$x=\frac{0±\sqrt{36}}{2\left(-3\right)}$$

Take the square root of 36.

$$x=\frac{0±6}{2\left(-3\right)}$$

Multiply 2 times -3.

$$x=\frac{0±6}{-6}$$

Now solve the equation x=\frac{0±6}{-6} when ± is plus. Divide 6 by -6.

$$x=-1$$

Now solve the equation x=\frac{0±6}{-6} when ± is minus. Divide -6 by -6.

$$x=1$$

The equation is now solved.

$$x=-1 x=1$$