Solve -3{left(24-143/6right)}^2+143^2/12

$$-3 { \left(24- \frac{ 143 }{ 6 } \right) }^{ 2 } + \frac{ { 143 }^{ 2 } }{ 12 }$$

Evaluate

$$1704$$

Solution Steps

Subtract \frac{143}{6} from 24 to get \frac{1}{6}.

$$-3\times \left(\frac{1}{6}\right)^{2}+\frac{143^{2}}{12}$$

Calculate \frac{1}{6} to the power of 2 and get \frac{1}{36}.

$$-3\times \frac{1}{36}+\frac{143^{2}}{12}$$

Multiply -3 and \frac{1}{36} to get -\frac{1}{12}.

$$-\frac{1}{12}+\frac{143^{2}}{12}$$

Calculate 143 to the power of 2 and get 20449.

$$-\frac{1}{12}+\frac{20449}{12}$$

Add -\frac{1}{12} and \frac{20449}{12} to get 1704.

$$1704$$

Factor

$$2^{3}\times 3\times 71$$