Solve -3{left(23-143/6right)}^2+143^2/12

$$-3 { \left(23- \frac{ 143 }{ 6 } \right) }^{ 2 } + \frac{ { 143 }^{ 2 } }{ 12 }$$

Evaluate

$$1702$$

Solution Steps

Subtract \frac{143}{6} from 23 to get -\frac{5}{6}.

$$-3\left(-\frac{5}{6}\right)^{2}+\frac{143^{2}}{12}$$

Calculate -\frac{5}{6} to the power of 2 and get \frac{25}{36}.

$$-3\times \frac{25}{36}+\frac{143^{2}}{12}$$

Multiply -3 and \frac{25}{36} to get -\frac{25}{12}.

$$-\frac{25}{12}+\frac{143^{2}}{12}$$

Calculate 143 to the power of 2 and get 20449.

$$-\frac{25}{12}+\frac{20449}{12}$$

Add -\frac{25}{12} and \frac{20449}{12} to get 1702.

$$1702$$

Factor

$$2\times 23\times 37$$