Solve -33/5left(2/3-275right)

$$-3 \frac{ 3 }{ 5 } \left( \frac{ 2 }{ 3 } -275 \right)$$

Evaluate

$$\frac{4938}{5}=987.6$$

Solution Steps

Multiply 3 and 5 to get 15.

$$\left(-\frac{15+3}{5}\right)\left(\frac{2}{3}-275\right)$$

Add 15 and 3 to get 18.

$$-\frac{18}{5}\left(\frac{2}{3}-275\right)$$

Convert 275 to fraction \frac{825}{3}.

$$-\frac{18}{5}\left(\frac{2}{3}-\frac{825}{3}\right)$$

Since \frac{2}{3} and \frac{825}{3} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{18}{5}\times \frac{2-825}{3}$$

Subtract 825 from 2 to get -823.

$$-\frac{18}{5}\left(-\frac{823}{3}\right)$$

Multiply -\frac{18}{5} times -\frac{823}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-18\left(-823\right)}{5\times 3}$$

Do the multiplications in the fraction \frac{-18\left(-823\right)}{5\times 3}.

$$\frac{14814}{15}$$

Reduce the fraction \frac{14814}{15} to lowest terms by extracting and canceling out 3.

$$\frac{4938}{5}$$

Factor

$$\frac{2 \cdot 3 \cdot 823}{5} = 987\frac{3}{5} = 987.6$$