Solve -3*2+3-22^2left(2*2-3right)^2

$$-3 \cdot 2+3-2 { 2 }^{ 2 } { \left( 2 \cdot 2-3 \right) }^{ 2 }$$

Evaluate

$$-11$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$-3\times 2+3-2^{3}\left(2\times 2-3\right)^{2}$$

Multiply -3 and 2 to get -6.

$$-6+3-2^{3}\left(2\times 2-3\right)^{2}$$

Add -6 and 3 to get -3.

$$-3-2^{3}\left(2\times 2-3\right)^{2}$$

Calculate 2 to the power of 3 and get 8.

$$-3-8\left(2\times 2-3\right)^{2}$$

Multiply 2 and 2 to get 4.

$$-3-8\left(4-3\right)^{2}$$

Subtract 3 from 4 to get 1.

$$-3-8\times 1^{2}$$

Calculate 1 to the power of 2 and get 1.

$$-3-8\times 1$$

Multiply 8 and 1 to get 8.

$$-3-8$$

Subtract 8 from -3 to get -11.

$$-11$$

Factor

$$-11$$