Solve -2xxyz*(-1/4)xyz

$$-2xxyz \times (- \frac{ 1 }{ 4 } )xyz$$

Evaluate

$$\frac{x^{3}\left(yz\right)^{2}}{2}$$

Solution Steps

Multiply x and x to get x^{2}.

$$-2x^{2}yz\left(-\frac{1}{4}\right)xyz$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$-2x^{3}yz\left(-\frac{1}{4}\right)yz$$

Multiply y and y to get y^{2}.

$$-2x^{3}y^{2}z\left(-\frac{1}{4}\right)z$$

Multiply z and z to get z^{2}.

$$-2x^{3}y^{2}z^{2}\left(-\frac{1}{4}\right)$$

Express -2\left(-\frac{1}{4}\right) as a single fraction.

$$\frac{-2\left(-1\right)}{4}x^{3}y^{2}z^{2}$$

Multiply -2 and -1 to get 2.

$$\frac{2}{4}x^{3}y^{2}z^{2}$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$\frac{1}{2}x^{3}y^{2}z^{2}$$

Differentiate w.r.t. x

$$\frac{3\left(xyz\right)^{2}}{2}$$