Solve for x
x=-\frac{3z}{2}+3
Solve for z
z=-\frac{2x}{3}+2
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-2x-3z=-6
Subtract 6 from both sides. Anything subtracted from zero gives its negation.
-2x=-6+3z
Add 3z to both sides.
-2x=3z-6
The equation is in standard form.
\frac{-2x}{-2}=\frac{3z-6}{-2}
Divide both sides by -2.
x=\frac{3z-6}{-2}
Dividing by -2 undoes the multiplication by -2.
x=-\frac{3z}{2}+3
Divide -6+3z by -2.
6-3z=2x
Add 2x to both sides. Anything plus zero gives itself.
-3z=2x-6
Subtract 6 from both sides.
\frac{-3z}{-3}=\frac{2x-6}{-3}
Divide both sides by -3.
z=\frac{2x-6}{-3}
Dividing by -3 undoes the multiplication by -3.
z=-\frac{2x}{3}+2
Divide -6+2x by -3.
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