Solve -2x+3y+6=0

$$-2x+3y+6 = 0$$

Solve for x

$$x=\frac{3\left(y+2\right)}{2}$$

Steps for Solving Linear Equation

Subtract 3y from both sides. Anything subtracted from zero gives its negation.

$$-2x+6=-3y$$

Subtract 6 from both sides.

$$-2x=-3y-6$$

Divide both sides by -2.

$$\frac{-2x}{-2}=\frac{-3y-6}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$x=\frac{-3y-6}{-2}$$

Divide -3y-6 by -2.

$$x=\frac{3y}{2}+3$$

Solve for y

$$y=\frac{2\left(x-3\right)}{3}$$

Steps for Solving Linear Equation

Add 2x to both sides. Anything plus zero gives itself.

$$3y+6=2x$$

Subtract 6 from both sides.

$$3y=2x-6$$

Divide both sides by 3.

$$\frac{3y}{3}=\frac{2x-6}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=\frac{2x-6}{3}$$

Divide -6+2x by 3.

$$y=\frac{2x}{3}-2$$