Solve -288*35/72+(10625-5/12)*(-16)=

$$-288 \times \frac{ 35 }{ 72 } +(10625- \frac{ 5 }{ 12 } ) \times (-16)=$$

Evaluate

$$-\frac{510400}{3}\approx -170133.333333333$$

Solution Steps

Express -288\times \frac{35}{72} as a single fraction.

$$\frac{-288\times 35}{72}+\left(10625-\frac{5}{12}\right)\left(-16\right)$$

Multiply -288 and 35 to get -10080.

$$\frac{-10080}{72}+\left(10625-\frac{5}{12}\right)\left(-16\right)$$

Divide -10080 by 72 to get -140.

$$-140+\left(10625-\frac{5}{12}\right)\left(-16\right)$$

Convert 10625 to fraction \frac{127500}{12}.

$$-140+\left(\frac{127500}{12}-\frac{5}{12}\right)\left(-16\right)$$

Since \frac{127500}{12} and \frac{5}{12} have the same denominator, subtract them by subtracting their numerators.

$$-140+\frac{127500-5}{12}\left(-16\right)$$

Subtract 5 from 127500 to get 127495.

$$-140+\frac{127495}{12}\left(-16\right)$$

Express \frac{127495}{12}\left(-16\right) as a single fraction.

$$-140+\frac{127495\left(-16\right)}{12}$$

Multiply 127495 and -16 to get -2039920.

$$-140+\frac{-2039920}{12}$$

Reduce the fraction \frac{-2039920}{12} to lowest terms by extracting and canceling out 4.

$$-140-\frac{509980}{3}$$

Convert -140 to fraction -\frac{420}{3}.

$$-\frac{420}{3}-\frac{509980}{3}$$

Since -\frac{420}{3} and \frac{509980}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-420-509980}{3}$$

Subtract 509980 from -420 to get -510400.

$$-\frac{510400}{3}$$

Factor

$$-\frac{510400}{3} = -170133\frac{1}{3} = -170133.33333333334$$