Solve -2(3+1/3y)+3y=-13

$$-2(3+ \frac{ 1 }{ 3 } y)+3y=-13$$

Solve for y

$$y=-3$$

Steps for Solving Linear Equation

Use the distributive property to multiply -2 by 3+\frac{1}{3}y.

$$-6-2\times \frac{1}{3}y+3y=-13$$

Multiply -2 and \frac{1}{3} to get \frac{-2}{3}.

$$-6+\frac{-2}{3}y+3y=-13$$

Fraction \frac{-2}{3} can be rewritten as -\frac{2}{3} by extracting the negative sign.

$$-6-\frac{2}{3}y+3y=-13$$

Combine -\frac{2}{3}y and 3y to get \frac{7}{3}y.

$$-6+\frac{7}{3}y=-13$$

Add 6 to both sides.

$$\frac{7}{3}y=-13+6$$

Add -13 and 6 to get -7.

$$\frac{7}{3}y=-7$$

Multiply both sides by \frac{3}{7}, the reciprocal of \frac{7}{3}.

$$y=-7\times \frac{3}{7}$$

Multiply -7 times \frac{3}{7}.

$$y=-3$$