Solve -2+y=4/3+1/3y

$$-2+y = \frac{ 4 }{ 3 } + \frac{ 1 }{ 3 } y$$

Solve for y

$$y=5$$

Steps for Solving Linear Equation

Subtract \frac{1}{3}y from both sides.

$$-2+y-\frac{1}{3}y=\frac{4}{3}$$

Combine y and -\frac{1}{3}y to get \frac{2}{3}y.

$$-2+\frac{2}{3}y=\frac{4}{3}$$

Add 2 to both sides.

$$\frac{2}{3}y=\frac{4}{3}+2$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{2}{3}y=\frac{4}{3}+\frac{6}{3}$$

Since \frac{4}{3} and \frac{6}{3} have the same denominator, add them by adding their numerators.

$$\frac{2}{3}y=\frac{4+6}{3}$$

Add 4 and 6 to get 10.

$$\frac{2}{3}y=\frac{10}{3}$$

Multiply both sides by \frac{3}{2}, the reciprocal of \frac{2}{3}.

$$y=\frac{10}{3}\times \frac{3}{2}$$

Multiply \frac{10}{3} times \frac{3}{2} by multiplying numerator times numerator and denominator times denominator.

$$y=\frac{10\times 3}{3\times 2}$$

Cancel out 3 in both numerator and denominator.

$$y=\frac{10}{2}$$

Divide 10 by 2 to get 5.

$$y=5$$