Skip to main content
Factor
Tick mark Image
Evaluate
Tick mark Image
Graph

Similar Problems from Web Search

Share

\frac{2\left(-3x^{2}+10x-3\right)}{3}
Factor out \frac{2}{3}.
a+b=10 ab=-3\left(-3\right)=9
Consider -3x^{2}+10x-3. Factor the expression by grouping. First, the expression needs to be rewritten as -3x^{2}+ax+bx-3. To find a and b, set up a system to be solved.
1,9 3,3
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 9.
1+9=10 3+3=6
Calculate the sum for each pair.
a=9 b=1
The solution is the pair that gives sum 10.
\left(-3x^{2}+9x\right)+\left(x-3\right)
Rewrite -3x^{2}+10x-3 as \left(-3x^{2}+9x\right)+\left(x-3\right).
3x\left(-x+3\right)-\left(-x+3\right)
Factor out 3x in the first and -1 in the second group.
\left(-x+3\right)\left(3x-1\right)
Factor out common term -x+3 by using distributive property.
\frac{2\left(-x+3\right)\left(3x-1\right)}{3}
Rewrite the complete factored expression.