Solve -2sqrt{2}=-sqrt{8}

$$-2 \sqrt{ 2 } =- \sqrt{ 8 }$$

Verify

Solution Steps

Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.

$$-2\sqrt{2}=-2\sqrt{2}$$

Add 2\sqrt{2} to both sides.

$$-2\sqrt{2}+2\sqrt{2}=0$$

Combine -2\sqrt{2} and 2\sqrt{2} to get 0.

$$0=0$$

Compare 0 and 0.

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