Solve -16x+3-5/2=0

$$-16x+3- \frac{ 5 }{ 2 } =0$$

Solve for x

$$x=\frac{1}{32}=0.03125$$

Steps for Solving Linear Equation

Convert 3 to fraction \frac{6}{2}.

$$-16x+\frac{6}{2}-\frac{5}{2}=0$$

Since \frac{6}{2} and \frac{5}{2} have the same denominator, subtract them by subtracting their numerators.

$$-16x+\frac{6-5}{2}=0$$

Subtract 5 from 6 to get 1.

$$-16x+\frac{1}{2}=0$$

Subtract \frac{1}{2} from both sides. Anything subtracted from zero gives its negation.

$$-16x=-\frac{1}{2}$$

Divide both sides by -16.

$$x=\frac{-\frac{1}{2}}{-16}$$

Express \frac{-\frac{1}{2}}{-16} as a single fraction.

$$x=\frac{-1}{2\left(-16\right)}$$

Multiply 2 and -16 to get -32.

$$x=\frac{-1}{-32}$$

Fraction \frac{-1}{-32} can be simplified to \frac{1}{32} by removing the negative sign from both the numerator and the denominator.

$$x=\frac{1}{32}$$