Solve -13+sqrt{x+3+x}=12

$$-13+ \sqrt{ x+3+x } =12$$

Solve for x

$$x=311$$

Steps for Solving Radical Equations

Combine x and x to get 2x.

$$-13+\sqrt{2x+3}=12$$

Add 13 to both sides.

$$\sqrt{2x+3}=12+13$$

Add 12 and 13 to get 25.

$$\sqrt{2x+3}=25$$

Square both sides of the equation.

$$2x+3=625$$

Subtract 3 from both sides of the equation.

$$2x+3-3=625-3$$

Subtracting 3 from itself leaves 0.

$$2x=625-3$$

Subtract 3 from 625.

$$2x=622$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{622}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{622}{2}$$

Divide 622 by 2.

$$x=311$$