Solve -11+7-2(-4+1-lfloor-2(-3+4)-2+4+7-8rfloor-4)=

$$-11+7-2(-4+1- \lfloor -2(-3+4)-2+4+7-8 \rfloor -4)=$$

Evaluate

$$8$$

Solution Steps

Add -11 and 7 to get -4.

$$-4-2\left(-4+1-\lfloor -2\left(-3+4\right)-2+4+7-8\rfloor -4\right)$$

Add -4 and 1 to get -3.

$$-4-2\left(-3-\lfloor -2\left(-3+4\right)-2+4+7-8\rfloor -4\right)$$

Add -3 and 4 to get 1.

$$-4-2\left(-3-\lfloor -2-2+4+7-8\rfloor -4\right)$$

Subtract 2 from -2 to get -4.

$$-4-2\left(-3-\lfloor -4+4+7-8\rfloor -4\right)$$

Add -4 and 4 to get 0.

$$-4-2\left(-3-\lfloor 7-8\rfloor -4\right)$$

Subtract 8 from 7 to get -1.

$$-4-2\left(-3-\lfloor -1\rfloor -4\right)$$

The floor of a real number a is the largest integer number less than or equal to a. The floor of -1 is -1.

$$-4-2\left(-3-\left(-1\right)-4\right)$$

The opposite of -1 is 1.

$$-4-2\left(-3+1-4\right)$$

Add -3 and 1 to get -2.

$$-4-2\left(-2-4\right)$$

Subtract 4 from -2 to get -6.

$$-4-2\left(-6\right)$$

Multiply 2 and -6 to get -12.

$$-4-\left(-12\right)$$

The opposite of -12 is 12.

$$-4+12$$

Add -4 and 12 to get 8.

$$8$$

Factor

$$2^{3}$$