Solve -10y^3*x/y^2+z=0

$$-10 { y }^{ 3 } \times \frac{ x }{ { y }^{ 2 } } +z=0$$

Solve for x

$$x=\frac{z}{10y}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by y^{2}.

$$-10y^{3}x+y^{2}z=0$$

Subtract y^{2}z from both sides. Anything subtracted from zero gives its negation.

$$-10y^{3}x=-y^{2}z$$

Reorder the terms.

$$-10xy^{3}=-zy^{2}$$

The equation is in standard form.

$$\left(-10y^{3}\right)x=-zy^{2}$$

Divide both sides by -10y^{3}.

$$\frac{\left(-10y^{3}\right)x}{-10y^{3}}=-\frac{zy^{2}}{-10y^{3}}$$

Dividing by -10y^{3} undoes the multiplication by -10y^{3}.

$$x=-\frac{zy^{2}}{-10y^{3}}$$

Divide -zy^{2} by -10y^{3}.

$$x=\frac{z}{10y}$$

Solve for y

$$\left\{\begin{matrix}y=\frac{z}{10x}\text{, }&x\neq 0\text{ and }z\neq 0\\y\neq 0\text{, }&z=0\text{ and }x=0\end{matrix}\right.$$