Solve -15/9*21/7+17/12=

$$-1 \frac{ 5 }{ 9 } \times 2 \frac{ 1 }{ 7 } +1 \frac{ 7 }{ 12 } =$$

Evaluate

$$-\frac{7}{4}=-1.75$$

Solution Steps

Multiply 1 and 9 to get 9.

$$\left(-\frac{9+5}{9}\right)\times \frac{2\times 7+1}{7}+\frac{1\times 12+7}{12}$$

Add 9 and 5 to get 14.

$$-\frac{14}{9}\times \frac{2\times 7+1}{7}+\frac{1\times 12+7}{12}$$

Multiply 2 and 7 to get 14.

$$-\frac{14}{9}\times \frac{14+1}{7}+\frac{1\times 12+7}{12}$$

Add 14 and 1 to get 15.

$$-\frac{14}{9}\times \frac{15}{7}+\frac{1\times 12+7}{12}$$

Multiply -\frac{14}{9} times \frac{15}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-14\times 15}{9\times 7}+\frac{1\times 12+7}{12}$$

Do the multiplications in the fraction \frac{-14\times 15}{9\times 7}.

$$\frac{-210}{63}+\frac{1\times 12+7}{12}$$

Reduce the fraction \frac{-210}{63} to lowest terms by extracting and canceling out 21.

$$-\frac{10}{3}+\frac{1\times 12+7}{12}$$

Multiply 1 and 12 to get 12.

$$-\frac{10}{3}+\frac{12+7}{12}$$

Add 12 and 7 to get 19.

$$-\frac{10}{3}+\frac{19}{12}$$

Least common multiple of 3 and 12 is 12. Convert -\frac{10}{3} and \frac{19}{12} to fractions with denominator 12.

$$-\frac{40}{12}+\frac{19}{12}$$

Since -\frac{40}{12} and \frac{19}{12} have the same denominator, add them by adding their numerators.

$$\frac{-40+19}{12}$$

Add -40 and 19 to get -21.

$$\frac{-21}{12}$$

Reduce the fraction \frac{-21}{12} to lowest terms by extracting and canceling out 3.

$$-\frac{7}{4}$$

Factor

$$-\frac{7}{4} = -1\frac{3}{4} = -1.75$$