Solve -0.02left(x-150right)^2+450=418

$$-0.02 { \left(x-150 \right) }^{ 2 } +450=418$$

Solve for x

$$x=190$$

$$x=110$$

Steps by Finding Square Root

Subtract 450 from both sides of the equation.

$$-0.02\left(x-150\right)^{2}+450-450=418-450$$

Subtracting 450 from itself leaves 0.

$$-0.02\left(x-150\right)^{2}=418-450$$

Subtract 450 from 418.

$$-0.02\left(x-150\right)^{2}=-32$$

Multiply both sides by -50.

$$\frac{-0.02\left(x-150\right)^{2}}{-0.02}=-\frac{32}{-0.02}$$

Dividing by -0.02 undoes the multiplication by -0.02.

$$\left(x-150\right)^{2}=-\frac{32}{-0.02}$$

Divide -32 by -0.02 by multiplying -32 by the reciprocal of -0.02.

$$\left(x-150\right)^{2}=1600$$

Take the square root of both sides of the equation.

$$x-150=40 x-150=-40$$

Add 150 to both sides of the equation.

$$x-150-\left(-150\right)=40-\left(-150\right) x-150-\left(-150\right)=-40-\left(-150\right)$$

Subtracting -150 from itself leaves 0.

$$x=40-\left(-150\right) x=-40-\left(-150\right)$$

Subtract -150 from 40.

$$x=190$$

Subtract -150 from -40.

$$x=110$$

The equation is now solved.

$$x=190 x=110$$