Solve -(4*8^2-8^2)+(4*8^2+4*8-3)

$$-(4 \times { 8 }^{ 2 } - { 8 }^{ 2 } )+(4 \times { 8 }^{ 2 } +4 \times 8-3)$$

Evaluate

$$93$$

Solution Steps

Calculate 8 to the power of 2 and get 64.

$$-\left(4\times 64-8^{2}\right)+4\times 8^{2}+4\times 8-3$$

Multiply 4 and 64 to get 256.

$$-\left(256-8^{2}\right)+4\times 8^{2}+4\times 8-3$$

Calculate 8 to the power of 2 and get 64.

$$-\left(256-64\right)+4\times 8^{2}+4\times 8-3$$

Subtract 64 from 256 to get 192.

$$-192+4\times 8^{2}+4\times 8-3$$

Calculate 8 to the power of 2 and get 64.

$$-192+4\times 64+4\times 8-3$$

Multiply 4 and 64 to get 256.

$$-192+256+4\times 8-3$$

Add -192 and 256 to get 64.

$$64+4\times 8-3$$

Multiply 4 and 8 to get 32.

$$64+32-3$$

Add 64 and 32 to get 96.

$$96-3$$

Subtract 3 from 96 to get 93.

$$93$$

Factor

$$3\times 31$$