Solve -(15-18*1^0)-(-((7-19)-9^2+25*3)-53)

$$-(15-18 \times { 1 }^{ 0 } )-(-((7-19)- { 9 }^{ 2 } +25 \times 3)-53)$$

Evaluate

$$38$$

Solution Steps

Calculate 1 to the power of 0 and get 1.

$$-\left(15-18\times 1\right)-\left(-\left(7-19-9^{2}+25\times 3\right)-53\right)$$

Multiply 18 and 1 to get 18.

$$-\left(15-18\right)-\left(-\left(7-19-9^{2}+25\times 3\right)-53\right)$$

Subtract 18 from 15 to get -3.

$$-\left(-3\right)-\left(-\left(7-19-9^{2}+25\times 3\right)-53\right)$$

The opposite of -3 is 3.

$$3-\left(-\left(7-19-9^{2}+25\times 3\right)-53\right)$$

Subtract 19 from 7 to get -12.

$$3-\left(-\left(-12-9^{2}+25\times 3\right)-53\right)$$

Calculate 9 to the power of 2 and get 81.

$$3-\left(-\left(-12-81+25\times 3\right)-53\right)$$

Subtract 81 from -12 to get -93.

$$3-\left(-\left(-93+25\times 3\right)-53\right)$$

Multiply 25 and 3 to get 75.

$$3-\left(-\left(-93+75\right)-53\right)$$

Add -93 and 75 to get -18.

$$3-\left(-\left(-18\right)-53\right)$$

The opposite of -18 is 18.

$$3-\left(18-53\right)$$

Subtract 53 from 18 to get -35.

$$3-\left(-35\right)$$

The opposite of -35 is 35.

$$3+35$$

Add 3 and 35 to get 38.

$$38$$

Factor

$$2\times 19$$