Solve -(-(-(-4-2)div-3-(2+5)-3*(4+2))-1)

$$-(-(-(-4-2) \div -3-(2+5)-3 \times (4+2))-1)$$

Evaluate

$$-26$$

Solution Steps

Subtract 2 from -4 to get -6.

$$-\left(-\left(\frac{-\left(-6\right)}{-3}-\left(2+5\right)-3\left(4+2\right)\right)-1\right)$$

The opposite of -6 is 6.

$$-\left(-\left(\frac{6}{-3}-\left(2+5\right)-3\left(4+2\right)\right)-1\right)$$

Divide 6 by -3 to get -2.

$$-\left(-\left(-2-\left(2+5\right)-3\left(4+2\right)\right)-1\right)$$

Add 2 and 5 to get 7.

$$-\left(-\left(-2-7-3\left(4+2\right)\right)-1\right)$$

Subtract 7 from -2 to get -9.

$$-\left(-\left(-9-3\left(4+2\right)\right)-1\right)$$

Add 4 and 2 to get 6.

$$-\left(-\left(-9-3\times 6\right)-1\right)$$

Multiply 3 and 6 to get 18.

$$-\left(-\left(-9-18\right)-1\right)$$

Subtract 18 from -9 to get -27.

$$-\left(-\left(-27\right)-1\right)$$

The opposite of -27 is 27.

$$-\left(27-1\right)$$

Subtract 1 from 27 to get 26.

$$-26$$

Factor

$$-26$$