Solve for x
x=\frac{y-3}{2}
Solve for y
y=2x+3
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-2x-3=-y
Swap sides so that all variable terms are on the left hand side.
-2x=-y+3
Add 3 to both sides.
-2x=3-y
The equation is in standard form.
\frac{-2x}{-2}=\frac{3-y}{-2}
Divide both sides by -2.
x=\frac{3-y}{-2}
Dividing by -2 undoes the multiplication by -2.
x=\frac{y-3}{2}
Divide -y+3 by -2.
-y=-2x-3
The equation is in standard form.
\frac{-y}{-1}=\frac{-2x-3}{-1}
Divide both sides by -1.
y=\frac{-2x-3}{-1}
Dividing by -1 undoes the multiplication by -1.
y=2x+3
Divide -2x-3 by -1.
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{ x } ^ { 2 } - 4 x - 5 = 0
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y = 3x + 4
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Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}