Solve for x
x=-3y-12
Solve for y
y=-\frac{x}{3}-4
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-x=12+3y
Add 3y to both sides.
-x=3y+12
The equation is in standard form.
\frac{-x}{-1}=\frac{3y+12}{-1}
Divide both sides by -1.
x=\frac{3y+12}{-1}
Dividing by -1 undoes the multiplication by -1.
x=-3y-12
Divide 12+3y by -1.
-3y=12+x
Add x to both sides.
-3y=x+12
The equation is in standard form.
\frac{-3y}{-3}=\frac{x+12}{-3}
Divide both sides by -3.
y=\frac{x+12}{-3}
Dividing by -3 undoes the multiplication by -3.
y=-\frac{x}{3}-4
Divide 12+x by -3.
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