Solve for x
x=7-3y
Solve for y
y=\frac{7-x}{3}
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-x+7=3y
Add 3y to both sides. Anything plus zero gives itself.
-x=3y-7
Subtract 7 from both sides.
\frac{-x}{-1}=\frac{3y-7}{-1}
Divide both sides by -1.
x=\frac{3y-7}{-1}
Dividing by -1 undoes the multiplication by -1.
x=7-3y
Divide 3y-7 by -1.
-3y+7=x
Add x to both sides. Anything plus zero gives itself.
-3y=x-7
Subtract 7 from both sides.
\frac{-3y}{-3}=\frac{x-7}{-3}
Divide both sides by -3.
y=\frac{x-7}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{7-x}{3}
Divide x-7 by -3.
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